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time: don't inline EXPORT_SYMBOL functions

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How is the compiler even handling exported functions that are marked
inline? Anyway, these shouldn't be inline because of that, so remove
that marking.

Based on a larger patch by Mark Charlebois to get LLVM to build the
kernel.

Cc: Thomas Gleixner <[email protected]>
Cc: Mark Charlebois <[email protected]>
Cc: Paul Gortmaker <[email protected]>
Cc: hank <[email protected]>
Cc: John Stultz <[email protected]>
Signed-off-by: Greg Kroah-Hartman <[email protected]>
Signed-off-by: Andrew Morton <[email protected]>
Signed-off-by: Linus Torvalds <[email protected]>
This commit is contained in:
Greg Kroah-Hartman authored and Linus Torvalds committed 2013-02-21 17:22:19 -08:00
1 parent f3d8496e9c
commit af3b56289b
1 file changed
+2 -2
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kernel/time.c
+2 -2
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@@ -240,7 +240,7 @@ EXPORT_SYMBOL(current_fs_time);
* Avoid unnecessary multiplications/divisions in the
* two most common HZ cases:
*/
inline unsigned int jiffies_to_msecs(const unsigned long j)
unsigned int jiffies_to_msecs(const unsigned long j)
{
#if HZ <= MSEC_PER_SEC && !(MSEC_PER_SEC % HZ)
return (MSEC_PER_SEC / HZ) * j;
@@ -256,7 +256,7 @@ inline unsigned int jiffies_to_msecs(const unsigned long j)
}
EXPORT_SYMBOL(jiffies_to_msecs);
inline unsigned int jiffies_to_usecs(const unsigned long j)
unsigned int jiffies_to_usecs(const unsigned long j)
{
#if HZ <= USEC_PER_SEC && !(USEC_PER_SEC % HZ)
return (USEC_PER_SEC / HZ) * j;