tools, bpftool: Exit on error in function codegen

Currently, the codegen function might fail and return an error. But its
callers continue without checking its return value. Since codegen can
fail only in the unlikely case of the system running out of memory or
the static template being malformed, just exit(-1) directly from codegen
and make it void-returning.

Suggested-by: Andrii Nakryiko <[email protected]>
Signed-off-by: Tobias Klauser <[email protected]>
Signed-off-by: Daniel Borkmann <[email protected]>
Acked-by: Andrii Nakryiko <[email protected]>
Link: https://lore.kernel.org/bpf/[email protected]

tools/bpf/bpftool/gen.c

@@ -200,7 +200,7 @@ out:
 	return err;
 }
 
-static int codegen(const char *template, ...)
+static void codegen(const char *template, ...)
 {
 	const char *src, *end;
 	int skip_tabs = 0, n;
@@ -211,7 +211,7 @@ static int codegen(const char *template, ...)
 	n = strlen(template);
 	s = malloc(n + 1);
 	if (!s)
-		return -ENOMEM;
+		exit(-1);
 	src = template;
 	dst = s;
 
@@ -225,7 +225,7 @@ static int codegen(const char *template, ...)
 			p_err("unrecognized character at pos %td in template '%s'",
 			      src - template - 1, template);
 			free(s);
-			return -EINVAL;
+			exit(-1);
 		}
 	}
 
@@ -236,7 +236,7 @@ static int codegen(const char *template, ...)
 				p_err("not enough tabs at pos %td in template '%s'",
 				      src - template - 1, template);
 				free(s);
-				return -EINVAL;
+				exit(-1);
 			}
 		}
 		/* trim trailing whitespace */
@@ -257,7 +257,8 @@ static int codegen(const char *template, ...)
 	va_end(args);
 
 	free(s);
-	return n;
+	if (n)
+		exit(-1);
 }
 
 static int do_skeleton(int argc, char **argv)